Q
What is the output of console.log(outerVar); outside of outerFunction if var outerVar = 'Outer'; is defined inside outerFunction?

Answer & Solution

Answer: Option C
Solution:
Variables defined with var inside a function are not accessible outside of that function.
Related Questions on Average

How do you declare a function-scoped variable using ES6?

A). var

B). let

C). const

D). function

What is function scope in JavaScript?

A). Variables defined within a function

B). Variables defined outside a function

C). Variables defined within an object

D). Variables defined globally

What is the output of console.log(blockVar); outside of a block if let blockVar = 'Block'; is defined inside a block?

A). Block

B). undefined

C). Error

D). null

What is the output of console.log(innerVar); outside of exampleFunction if var innerVar = 'Hello'; is defined inside exampleFunction?

A). Hello

B). undefined

C). Error

D). null

What happens if you declare a variable with the same name in both function and block scopes?

A). It creates two separate variables

B). It causes an error

C). It combines the scopes

D). It prioritizes the function scope

Can function-scoped variables be accessed from outside their functions?

A). Yes

B). No

C). Only if they are constants

D). Only if they are defined globally

How can you access a variable declared in an inner block from an outer block?

A). Using the var keyword

B). Using the let keyword

C). Using the const keyword

D). Using the this keyword

What is hoisting in JavaScript?

A). Moving variables to the top of their function or global scope

B). Making variables undefined

C). Creating new variables

D). None of the above

What is lexical scoping in JavaScript?

A). Variables scoped to the entire codebase

B). Variables scoped to their functions

C). Variables scoped based on their position in the code

D). Variables scoped based on their names

Which keyword is used to declare a function-scoped variable?

A). var

B). let

C). const

D). function