Answer & Solution
Answer: Option B
Solution:
Variables declared with let can be accessed from outer blocks, but variables declared with var are function-scoped.
Q
How can you access a variable declared in an inner block from an outer block?
Related Questions on Average
What is the benefit of block scope in JavaScript?
A). It reduces variable conflicts
B). It increases global scope
C). It simplifies variable declarations
D). It makes variables inaccessible
What is block scope in JavaScript?
A). Variables scoped to a block
B). Variables scoped to a function
C). Variables scoped globally
D). Variables scoped locally
What is the purpose of function scope in JavaScript?
A). To limit the visibility of variables
B). To make variables global
C). To create constants
D). To execute functions
What is the output of console.log(blockVar); outside of a block if let blockVar = 'Block'; is defined inside a block?
A). Block
B). undefined
C). Error
D). null
What happens if you declare a variable with the same name in both function and block scopes?
A). It creates two separate variables
B). It causes an error
C). It combines the scopes
D). It prioritizes the function scope
What is lexical scoping in JavaScript?
A). Variables scoped to the entire codebase
B). Variables scoped to their functions
C). Variables scoped based on their position in the code
D). Variables scoped based on their names
Which of the following is true about function scope in JavaScript?
A). Variables are accessible globally
B). Variables are accessible only within their functions
C). Variables are accessible within an object
D). Variables are accessible everywhere in the code
How do you declare a function-scoped variable using ES6?
A). var
B). let
C). const
D). function
Which keyword is used to declare a function-scoped variable?
A). var
B). let
C). const
D). function
How do you declare a block-scoped variable in ES6?
A). var
B). let
C). const
D). function