How do you declare a function-scoped variable using ES6?
A). var
B). let
C). const
D). function
How can you access a variable declared in an inner block from an outer block?
A). Using the var keyword
B). Using the let keyword
C). Using the const keyword
D). Using the this keyword
What is the output of console.log(innerVar); outside of exampleFunction if var innerVar = 'Hello'; is defined inside exampleFunction?
A). Hello
B). undefined
C). Error
D). null
What happens if you declare a variable with the same name in both function and block scopes?
A). It creates two separate variables
B). It causes an error
C). It combines the scopes
D). It prioritizes the function scope
Which keyword is used to declare a function-scoped variable?
A). var
B). let
C). const
D). function
Which of the following is true about function scope in JavaScript?
A). Variables are accessible globally
B). Variables are accessible only within their functions
C). Variables are accessible within an object
D). Variables are accessible everywhere in the code
What is block scope in JavaScript?
A). Variables scoped to a block
B). Variables scoped to a function
C). Variables scoped globally
D). Variables scoped locally
What happens to a function-scoped variable outside of its function?
A). It becomes a global variable
B). It becomes a local variable
C). It is accessible only within the function
D). It throws an error
What is the output of console.log(blockVar); outside of a block if let blockVar = 'Block'; is defined inside a block?
A). Block
B). undefined
C). Error
D). null
What is the output of console.log(outerVar); outside of outerFunction if var outerVar = 'Outer'; is defined inside outerFunction?
A). Outer
B). undefined
C). Error
D). null