Q
What happens if you declare a variable with the same name in both function and block scopes?

Answer & Solution

Answer: Option A
Solution:
Declaring a variable with the same name in both function and block scopes creates two separate variables with distinct scopes.
Related Questions on Average

What happens to a function-scoped variable outside of its function?

A). It becomes a global variable

B). It becomes a local variable

C). It is accessible only within the function

D). It throws an error

What is the benefit of block scope in JavaScript?

A). It reduces variable conflicts

B). It increases global scope

C). It simplifies variable declarations

D). It makes variables inaccessible

Which of the following demonstrates lexical scoping?

A). Closure

B). Hoisting

C). Global scope

D). Local scope

How can you access a variable declared in an inner block from an outer block?

A). Using the var keyword

B). Using the let keyword

C). Using the const keyword

D). Using the this keyword

What is the output of console.log(innerVar); outside of exampleFunction if var innerVar = 'Hello'; is defined inside exampleFunction?

A). Hello

B). undefined

C). Error

D). null

What is the purpose of function scope in JavaScript?

A). To limit the visibility of variables

B). To make variables global

C). To create constants

D). To execute functions

What is function scope in JavaScript?

A). Variables defined within a function

B). Variables defined outside a function

C). Variables defined within an object

D). Variables defined globally

Can function-scoped variables be accessed from outside their functions?

A). Yes

B). No

C). Only if they are constants

D). Only if they are defined globally

How do you declare a function-scoped variable using ES6?

A). var

B). let

C). const

D). function

What is lexical scoping in JavaScript?

A). Variables scoped to the entire codebase

B). Variables scoped to their functions

C). Variables scoped based on their position in the code

D). Variables scoped based on their names