Q
Which PHP feature allows defining functions with a variable number of arguments?

Answer & Solution

Answer: Option C
Solution:
Variable arguments (also known as varargs) in PHP allow defining functions with a variable number of arguments. This feature is achieved using the ...$args syntax in the function definition, allowing the function to accept any number of arguments.
Related Questions on Average

Which PHP keyword is used to define functions without specifying their names?

A). Dynamic functions

B). Anonymous functions

C). Inner functions

D). Nested functions

Which keyword is used to define default parameter values in PHP functions?

A). default

B). var

C). const

D). None of the above

What will be the output of the following PHP code?
<?php
$greet = function($name) {
return 'Hello, $name!';
};
echo $greet('John');
?

A). Hello, John!

B). Hello, $name!

C). function($name) { return 'Hello, $name!'; }

D). John

Which PHP feature allows defining functions within other functions?

A). Inner functions

B). Enclosed functions

C). Nested functions

D). All of the above

What will be the output of the following PHP code?
<?php
function sum($a, $b = 5) {
return $a + $b;
}
echo sum(3);
?

A). 3

B). 8

C). 5

D). Function call will result in an error

Which PHP feature allows defining functions with variable-length argument lists?

A). Dynamic functions

B). Variable arguments

C). Varargs

D). All of the above

What will be the output of the following PHP code?
<?php
function greet() {
echo 'Hello, World!';
}
if (function_exists('greet')) {
greet();
} else {
echo 'Function does not exist';
}
?

A). Hello, World!

B). Function does not exist

C). Undefined function: greet

D). Function greet() { echo 'Hello, World!'; }

What will be the output of the following PHP code?
<?php
function add($a, $b) {
return $a + $b;
}
$result = add(5, 3);
echo $result;
?

A). 8

B). add(5, 3)

C). function add($a, $b) { return $a + $b; }

D). $a + $b

What will be the output of the following PHP code?
<?php
function factorial($n) {
$result = 1;
for ($i = 1; $i <= $n; $i++) {
$result *= $i;
}
return $result;
}
echo factorial(5);
?

A). 120

B). 5

C). Undefined function: factorial

D). Function factorial($n) { $result = 1; for ($i = 1; $i <= $n; $i++) { $result *= $i; } return $result; }

What is the significance of passing functions as arguments in PHP?

A). It allows functions to be called multiple times

B). It simplifies the function definition process

C). It enables dynamic function invocation and behavior

D). It prevents code duplication