Q
What will be the output of the following code? let name = 'Alice'; let Name = 'Bob'; console.log(name, Name);

Answer & Solution

Answer: Option A
Solution:
The output will be 'Alice Bob' because 'name' and 'Name' are different variables.
Related Questions on Average

Which of the following function names are considered identical in JavaScript?

A). myFunction and MyFunction

B). myfunction and myFunction

C). myFunction and myfunction

D). None of the above

In JavaScript, is 'myVariable' the same as 'myvariable'?

A). Yes

B). No

C). Depends on the context

D). Only in strict mode

Is 'myfunction' the same as 'myFunction' in JavaScript?

A). Yes

B). No

C). Only in strict mode

D). Only in non-strict mode

How does JavaScript differentiate between 'myVar' and 'MyVar'?

A). It doesn't, both are the same

B). It treats them as different variables

C). It throws an error

D). None of the above

How will JavaScript handle 'VarName' and 'varName' in the same scope?

A). Treat as the same

B). Treat as different

C). Throw an error

D). Ignore one

What is the significance of case sensitivity in JavaScript?

A). Enhances code readability

B). Reduces code size

C). Improves performance

D). Differentiates identifiers

What happens if you try to declare two variables with the same name but different cases?

A). Error

B). Both are declared

C). Only one is declared

D). None of the above

How should constants be declared to avoid confusion with variable names?

A). UPPERCASE

B). lowercase

C). camelCase

D). snake_case

How does JavaScript interpret the following? let varName = 5; let VarName = 10; console.log(varName, VarName);

A). 5 5

B). 10 10

C). 5 10

D). 10 5

What is the effect of case sensitivity on debugging JavaScript code?

A). No effect

B). Makes it easier

C). Makes it harder

D). No significant impact