Q
What will be the output of the following code? let name = 'Alice'; let Name = 'Bob'; console.log(name, Name);

Answer & Solution

Answer: Option A
Solution:
The output will be 'Alice Bob' because 'name' and 'Name' are different variables.
Related Questions on Average

What is the best practice for naming variables to avoid issues with case sensitivity?

A). Use only lowercase

B). Use only UPPERCASE

C). Use consistent case conventions

D). Use special characters

How should constants be declared to avoid confusion with variable names?

A). UPPERCASE

B). lowercase

C). camelCase

D). snake_case

In JavaScript, is 'myVariable' the same as 'myvariable'?

A). Yes

B). No

C). Depends on the context

D). Only in strict mode

How does JavaScript differentiate between 'myFunction()' and 'myfunction()'?

A). As the same function

B). As different functions

C). As a syntax error

D). As a reserved keyword

How will JavaScript handle 'VarName' and 'varName' in the same scope?

A). Treat as the same

B). Treat as different

C). Throw an error

D). Ignore one

Which of the following statements is true about case sensitivity in JavaScript?

A). Variable names are case-insensitive

B). Function names are case-insensitive

C). Identifiers are case-sensitive

D). All of the above

How does JavaScript treat 'Function()' and 'function()'?

A). As the same function

B). As different functions

C). As a syntax error

D). As a reserved keyword

Which of the following is a correct variable declaration in JavaScript?

A). var Variable = 1;

B). var variable = 1;

C). Both A and B

D). None of the above

What happens if you try to declare two variables with the same name but different cases?

A). Error

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C). Only one is declared

D). None of the above

What is the significance of case sensitivity in JavaScript?

A). Enhances code readability

B). Reduces code size

C). Improves performance

D). Differentiates identifiers