Q
What will be the output of the code above?

Answer & Solution

Answer: Option A
Solution:
The output will be 10. Although x is declared again within the block, it creates a new block-scoped variable, so the outer x remains unchanged with a value of 10.
Related Questions on Average

Which statement about JavaScript's const is true?

A). const variables can be redeclared

B). const variables are globally scoped

C). const variables are mutable

D). const variables cannot be reassigned

What is the primary advantage of using block scope in JavaScript?

A). Reducing code size

B). Preventing variable hoisting

C). Avoiding global variables

D). Improving performance

What will be the output of the code above?

A). 30

B). 31

C). Error

D). Undefined

What will happen when you try to execute this code?

A). 14 will be logged to the console

B). 14159 will be logged to the console

C). SyntaxError will occur

D). TypeError will occur

Which of the following statements is true about block scope in JavaScript?

A). Variables declared with let have global scope

B). Variables declared with let have function scope

C). Variables declared with let are block-scoped

D). Variables declared with let are hoisted

What happens if you try to reassign a value to a constant declared using const?

A). SyntaxError

B). TypeError

C). ReferenceError

D). No error, value is reassigned

What is the benefit of using const over var in JavaScript?

A). const variables have function scope

B). const variables are hoisted to the top

C). const variables prevent accidental reassignments

D). const variables can be used anywhere

Which of the following is NOT an example of a block in JavaScript?

A). Function body

B). if statement body

C). while loop body

D). Object literal

Which of the following best describes the behavior of JavaScript's const keyword?

A). It prevents variables from being redeclared

B). It ensures variables cannot be reassigned

C). It provides global scope for variables

D). It allows variables to change their data type

What happens if you try to declare a const variable without initializing it immediately?

A). SyntaxError

B). ReferenceError

C). TypeError

D). No error, the variable remains undefined