Q
What happens when you redeclare a variable with 'var' inside a function?

Answer & Solution

Answer: Option A
Solution:
When you redeclare a variable with 'var' inside a function, the new declaration overwrites the previous one within that function's scope.
Related Questions on Average

What will happen if you try to use a variable before declaring it with 'let'?

A). It will return undefined

B). It will return null

C). It will throw a ReferenceError

D). It will return NaN

Can you redeclare a 'var' variable in a different scope without error?

A). Yes

B). No

C). Only in strict mode

D). Only if the variable is not initialized

What error is thrown when attempting to redeclare a 'const' variable?

A). TypeError

B). ReferenceError

C). SyntaxError

D). RangeError

Why is it recommended to use 'let' and 'const' over 'var' in modern JavaScript?

A). 'let' and 'const' are function-scoped

B). 'let' and 'const' prevent variable hoisting

C). 'let' and 'const' are block-scoped, reducing potential errors

D). 'let' and 'const' are faster

Can you redeclare a 'let' variable in the same scope in JavaScript?

A). Yes

B). No

C). Only in strict mode

D). Only in non-strict mode

Which of the following correctly describes variable hoisting with 'var'?

A). 'var' declarations are not hoisted

B). Only the variable declaration is hoisted, not the initialization

C). Both declaration and initialization are hoisted

D). Only in strict mode 'var' declarations are hoisted

Which of the following is a characteristic of 'const' variables?

A). They can be redeclared

B). They can be reassigned

C). They cannot be redeclared but can be reassigned

D). They cannot be redeclared or reassigned

What happens if you try to redeclare a 'const' variable in JavaScript?

A). It will throw an error

B). The variable is overwritten

C). The variable is converted to 'let'

D). The program continues with a warning

What will happen if you declare a 'let' variable inside a block and try to access it outside the block?

A). It will return undefined

B). It will throw a ReferenceError

C). It will return null

D). It will be accessible outside the block

What will be the result of executing 'let x = 1; let x = 2;' in the same scope?

A). x will be 1

B). x will be 2

C). Syntax Error

D). Runtime Error