Q
What happens if you try to declare two variables with the same name but different cases?

Answer & Solution

Answer: Option B
Solution:
Both variables will be declared as they are treated as different due to case sensitivity.
Related Questions on Average

Which of the following is a correct variable declaration in JavaScript?

A). var Variable = 1;

B). var variable = 1;

C). Both A and B

D). None of the above

What is the significance of case sensitivity in JavaScript?

A). Enhances code readability

B). Reduces code size

C). Improves performance

D). Differentiates identifiers

In JavaScript, is 'myVariable' the same as 'myvariable'?

A). Yes

B). No

C). Depends on the context

D). Only in strict mode

What will be the output of the following code? let name = 'Alice'; let Name = 'Bob'; console.log(name, Name);

A). Alice Bob

B). Bob Alice

C). Alice Alice

D). Bob Bob

How does JavaScript differentiate between 'myVar' and 'MyVar'?

A). It doesn't, both are the same

B). It treats them as different variables

C). It throws an error

D). None of the above

Is 'myfunction' the same as 'myFunction' in JavaScript?

A). Yes

B). No

C). Only in strict mode

D). Only in non-strict mode

What is the recommended naming convention for JavaScript functions?

A). camelCase

B). UPPERCASE

C). snake_case

D). PascalCase

How does JavaScript treat 'Function()' and 'function()'?

A). As the same function

B). As different functions

C). As a syntax error

D). As a reserved keyword

Can a function and a variable have the same name with different cases in JavaScript?

A). Yes

B). No

C). Only in strict mode

D). Only in non-strict mode

How does JavaScript differentiate between 'myFunction()' and 'myfunction()'?

A). As the same function

B). As different functions

C). As a syntax error

D). As a reserved keyword