Q
What happens if you do not close a multi-line comment in JavaScript?

Answer & Solution

Answer: Option B
Solution:
Not closing a multi-line comment results in a syntax error, as the interpreter expects the comment to be closed with */.
Related Questions on Average

How can multi-line comments aid in collaborative development?

A). By hiding code

B). By providing detailed explanations

C). By increasing code performance

D). By reducing code size

Where can you use multi-line comments in JavaScript?

A). Only outside functions

B). Only inside functions

C). Anywhere in the code

D). Only in global scope

How do you comment out a block of code using multi-line comments in JavaScript?

A). # code block

B). // code block

C).

D). /* code block */

Which statement about multi-line comments is accurate in JavaScript?

A). They are executed as code

B). They can contain nested multi-line comments

C). They are used for short explanations

D). They are ignored by the interpreter

What is the primary benefit of using multi-line comments in JavaScript?

A). Improved code execution

B). Better documentation

C). Faster code performance

D). Easier debugging

What is the primary difference between single-line and multi-line comments in JavaScript?

A). Single-line comments execute code

B). Multi-line comments span multiple lines

C). Single-line comments execute faster

D). Multi-line comments are executed as code

Which of the following is NOT a valid use of multi-line comments in JavaScript?

A). Writing executable code

B). Adding documentation

C). Temporarily disabling code

D). Adding notes

What can multi-line comments help improve in JavaScript code?

A). Code execution speed

B). Code documentation

C). Code readability

D). Code performance

Which of the following is the correct syntax for a multi-line comment in JavaScript?

A).

B). /* This is a comment */

C). # This is a comment

D). // This is a comment

How can multi-line comments be used effectively during debugging?

A). By adding unnecessary code blocks

B). By temporarily disabling code blocks

C). By increasing code complexity

D). By reducing code size