Q
How does block scope help prevent variable hoisting issues?

Answer & Solution

Answer: Option B
Solution:
Block scope confines variables to their block, preventing hoisting issues where variables are hoisted to the top of the function or global scope.
Related Questions on Average

What is the output of console.log(outerVar); outside outerFunction if let outerVar = 'Outer'; is declared inside outerFunction?

A). Outer

B). undefined

C). Error

D). null

What is lexical scoping in JavaScript?

A). Variables scoped to the entire codebase

B). Variables scoped to their functions

C). Variables scoped based on their position in the code

D). Variables scoped based on their names

Which of the following correctly defines a block scope?

A). A scope that encompasses the entire codebase

B). A scope that encompasses a function

C). A scope that encompasses a block of code delimited by curly braces

D). A scope that encompasses an object

How does block scope affect the visibility of variables in nested blocks?

A). Variables are only visible within their immediate block

B). Variables are visible within all nested blocks

C). Variables are only visible within functions

D). Variables are globally visible

How can you access a variable declared in an inner block from an outer block?

A). Using the var keyword

B). Using the let keyword

C). Using the const keyword

D). Using the this keyword

What is the output of console.log(innerVar); outside exampleFunction if let innerVar = 'Hello'; is declared inside exampleFunction?

A). Hello

B). undefined

C). Error

D). null

What happens if you try to access a block-scoped variable outside its block?

A). The variable is accessible globally

B). The variable is accessible within its block

C). An error occurs

D). The variable is accessible within a function

What is the purpose of block scope in JavaScript?

A). To limit the visibility and accessibility of variables

B). To make variables global

C). To create constants

D). To execute functions

What is hoisting in JavaScript?

A). Moving variables to the top of their function or global scope

B). Making variables undefined

C). Creating new variables

D). None of the above

What happens when you declare a constant with const inside a block and try to reassign it?

A). It throws an error

B). It allows reassignment

C). It assigns the value globally

D). It assigns a default value