Q
How do you shuffle the elements of an array in Underscore.js?

Answer & Solution

Answer: Option B
Solution:
The _.shuffle function returns a shuffled copy of the list, using a version of the Fisher-Yates shuffle.
Related Questions on Average

How do you debounce a function in Underscore.js to limit the rate at which it can fire?

A). _.throttle

B). _.debounce

C). _.delay

D). _.once

Which function is used to find unique elements in an array in Underscore.js?

A). _.first

B). _.last

C). _.uniq

D). _.filter

How do you check if a value is an array in Underscore.js?

A). _.isObject

B). _.isArray

C). _.isArguments

D). _.isString

What does _.keys({one: 1, two: 2, three: 3}) return?

A). [1, 2, 3]

B). ['one', 'two', 'three']

C). ['1', '2', '3']

D). [1, 2, 'three']

What does _.pluck([{a: 1}, {a: 2}, {a: 3}], 'a') return?

A). [1, 2, 3]

B). [1, 2]

C). [2, 3]

D). [3, 1]

What is the result of _.reduce([1, 2, 3], function(sum, num) { return sum + num; }, 0)?

A). 6

B). 5

C). 3

D). 2

How do you flatten a nested array using Underscore.js?

A). _.map

B). _.flatten

C). _.filter

D). _.reduce

Which function is used to clone an object in Underscore.js?

A). _.extend

B). _.clone

C). _.map

D). _.filter

What does _.identity(value) return?

A). null

B). undefined

C). The same value

D). A new value

What is the result of _.map([1, 2, 3], function(num) { return num * 3; })?

A). [1, 2, 3]

B). [3, 6, 9]

C). [2, 4, 6]

D). [3, 6, 9, 12]