Q
How do you get the index of the first occurrence of a specified substring in a string?

Answer & Solution

Answer: Option A
Solution:
The .indexOf(substring) method in JavaScript returns the index within the calling string object of the first occurrence of the specified substring.
Related Questions on Average

What is the result of 'Hello'.substring(0, 3) in JavaScript?

A). 'Hell'

B). 'Hello'

C). 'o'

D). 'llo'

How do you trim whitespace from the beginning and end of a string in JavaScript?

A). string.trim()

B). trimString(string)

C). string.strip()

D). trim(string)

How do you convert a string to uppercase in JavaScript?

A). string.toUpperCase()

B). string.uppercase()

C). string.toUppercase()

D). string.upperCase()

What does the .toLowerCase() method do in JavaScript?

A). Converts all characters to lowercase

B). Converts all characters to uppercase

C). Trims leading and trailing whitespace

D). Converts string to a boolean

What does the .substring() method do in JavaScript?

A). Extracts characters between two indices

B). Trims whitespace from the beginning

C). Converts string to an array

D). Compares two strings

How do you extract parts of a string and join them together in JavaScript?

A). string.slice(start, end)

B). string.extract(start, end)

C). string.split(start, end)

D). string.join(start, end)

What does the .concat() method do in JavaScript?

A). Concatenates two or more strings

B). Compares two strings

C). Converts a string to lowercase

D). Finds a substring in a string

What is the result of 'apple'.charAt(2) in JavaScript?

A). 'p'

B). 'l'

C). 'a'

D). 'pp'

What does the .replace() method do in JavaScript?

A). Replaces a specified value with another value

B). Removes a substring

C). Splits a string into an array

D). Joins two or more strings

How do you extract a part of a string and replace it with another substring in JavaScript?

A). string.replace(oldSubstring, newSubstring)

B). string.extractReplace(old, new)

C). string.modify(old, new)

D). string.substitute(old, new)