Q
How do you convert a string to uppercase in JavaScript?

Answer & Solution

Answer: Option A
Solution:
The .toUpperCase() method in JavaScript converts all characters in a string to uppercase.
Related Questions on Average

What does the .substring() method do in JavaScript?

A). Extracts characters between two indices

B). Trims whitespace from the beginning

C). Converts string to an array

D). Compares two strings

What does the .toLowerCase() method do in JavaScript?

A). Converts all characters to lowercase

B). Converts all characters to uppercase

C). Trims leading and trailing whitespace

D). Converts string to a boolean

How do you concatenate two strings in JavaScript?

A). string1.concat(string2)

B). string1 + string2

C). string1.join(string2)

D). string1.combine(string2)

What does the + operator do with strings?

A). Concatenates strings

B). Compares strings

C). Trims strings

D). Converts strings to uppercase

How do you extract parts of a string and join them together in JavaScript?

A). string.slice(start, end)

B). string.extract(start, end)

C). string.split(start, end)

D). string.join(start, end)

What does the .concat() method do in JavaScript?

A). Concatenates two or more strings

B). Compares two strings

C). Converts a string to lowercase

D). Finds a substring in a string

How do you extract a part of a string and replace it with another substring in JavaScript?

A). string.replace(oldSubstring, newSubstring)

B). string.extractReplace(old, new)

C). string.modify(old, new)

D). string.substitute(old, new)

How do you find the length of a string in JavaScript?

A). string.length

B). string.size

C). string.length()

D). lengthOf(string)

What is the correct way to compare two strings in JavaScript for equality?

A). string1 == string2

B). string1.compare(string2)

C). string1.equals(string2)

D). string1 === string2

How do you get the index of the first occurrence of a specified substring in a string?

A). string.indexOf(substring)

B). string.index(substring)

C). substring.positionIn(string)

D). string.search(substring)