Q
How can you avoid accidentally redeclaring variables in JavaScript?

Answer & Solution

Answer: Option D
Solution:
To avoid accidental variable redeclaration, use let or const for variable declarations within the same scope and declare variables once.
Related Questions on Average

What is the output of the following code snippet?

A). A. 10

B). B. 20

C). C. 30

D). D. Error

What is the behavior of a redeclared variable in JavaScript?

A). A. It retains its original value

B). B. It retains its last assigned value

C). C. It becomes undefined

D). D. It throws an error

What is the behavior when redeclaring a variable with var in JavaScript?

A). A. SyntaxError is thrown

B). B. No effect on the variable

C). C. Variable value is changed

D). D. Variable reference is updated

What is the result of the following code snippet?

A). A. SyntaxError is thrown

B). B. 20

C). C. 30

D). D. Error

What is the behavior of a redeclared variable in JavaScript with let or const within nested scopes?

A). A. It inherits the value from the outer scope

B). B. It retains its original value within the nested scope

C). C. It throws an error

D). D. It becomes undefined

What is the scope of a redeclared variable in JavaScript with let or const?

A). A. Global scope

B). B. Function scope

C). C. Block scope

D). D. Module scope

What is variable redeclaring in JavaScript?

A). A. Changing the value of a variable

B). B. Declaring the same variable again within the same scope

C). C. Deleting a variable

D). D. Assigning multiple values to a variable

Which keyword allows variable redeclaration in JavaScript?

A). A. var

B). B. let

C). C. const

D). D. none of the above

What is the result of the following code snippet?

A). A. SyntaxError is thrown

B). B. 10

C). C. 20

D). D. 30

Which statement about redeclaring variables in JavaScript is true?

A). A. Redeclaring variables is a best practice

B). B. Redeclaring variables leads to clearer code

C). C. Redeclaring variables can lead to confusion and bugs

D). D. Redeclaring variables has no effect